An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3 μT perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that the electron moves along the same path, is N C⁻¹. (Given, mass…

Question

An electron with kinetic energy 5 eV enters a region of uniform magnetic field of 3 μT perpendicular to its direction. An electric field E is applied perpendicular to the direction of velocity and magnetic field. The value of E, so that the electron moves along the same path, is N C⁻¹. (Given, mass of electron =9×10⁻³¹ kg, electric charge =1.6×10⁻¹⁹ C)

Accepted Answer

4. v=√(2K)/m=√(2×5×1.6×10⁻¹⁹)/(9×10⁻³¹)=4/3×10⁶ m/s No deflection when eE=evB⇒ E=vB E=4/3×10⁶×3×10⁻⁶=4 N/C → 4

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