A bullet of 4 g mass is fired from a gun of mass 4 kg. If the bullet moves with the muzzle speed of 50 m s⁻¹, the impulse imparted to the gun and velocity of recoil of gun are

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(3) 0.2 kg m s⁻¹, 0.05 m s⁻¹. Idea: gun and bullet start at rest, so the impulse on the gun is exactly the momentum the bullet leaves with; the recoil speed then follows from the gun's mass. m_b=4 g=0.004 kg. Impulse: |J|=m_bv=0.004×50=0.2 kg m s⁻¹. Recoil speed: the gun takes up that same momentum, V=(0.2)/4=0.05 m s⁻¹. The gun is a thousand times heavier than the bullet, so it moves a thousand times slower — 0.05 against 50 m s⁻¹.

A bullet of 4 g mass is fired from a gun of mass 4 kg. If the bullet moves with the muzzle speed of 50 m s⁻¹, the impulse imparted to the gun and velocity of recoil of gun are

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