A monkey of mass 50 kg climbs on a rope which can withstand the tension (T) of 350 N. If monkey initially climbs down with an acceleration of 4 m/s² and then climbs up with an acceleration of 5 m/s². Choose the correct option (g=10 m/s²)

Question

Accepted Answer

(3) Rope will break while climbing upward. Idea: climbing up needs the rope to supply more than the weight; climbing down needs it to supply less. Compare each with 350 N. Going down, acceleration 4 m/s² downward: mg-T=ma, so T=m(g-a)=50(10-4)=300 N. 300<350, so the rope holds. Climbing up, acceleration 5 m/s² upward: T-mg=ma, so T=m(g+a)=50(10+5)=750 N. 750>350, so the rope breaks while climbing upward. The monkey is in most danger going up, which is why the two accelerations are given in that order.

A monkey of mass 50 kg climbs on a rope which can withstand the tension (T) of 350 N. If monkey initially climbs down with an acceleration of 4 m/s² and then climbs up with an acceleration of 5 m/s². Choose the correct option (g=10 m/s²)

Step-by-step solution

Why the other options are wrong