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A gaseous mixture consists of 16 g of helium and 16 g of oxygen. The ratio C_P/C_V of the mixture is

Asked in AIEEE 2005 · Specific heats of a mixture

Answer: (4) 1.62

Step-by-step solution

Equal masses do not mean equal moles: helium n=(16)/4=4, oxygen n=(16)/(32)=0.5.

C_V: helium 3/2 R, oxygen 5/2 R.

C_V(mix)=(4(3/2 R)+0.5(5/2 R))/(4.5)=(6R+1.25R)/(4.5)=1.611R.

C_P=C_V+R=2.611R.

γ=(2.611)/(1.611)≈1.62.

Why the other options are wrong

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