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Let γ₁ be the ratio of molar specific heat at constant pressure to molar specific heat at constant volume of a monoatomic gas and γ₂ the similar ratio of a diatomic gas. Considering the diatomic molecule as a rigid rotator, the ratio γ₁/γ₂ is

Asked in JEE Main 24th Jan 2nd Shift 2023 · Ratio of specific heats

Answer: (2) (25)/(21)

Step-by-step solution

Monoatomic: f=3, so γ₁=1+2/3=5/3.

Rigid-rotator diatomic: f=5, so γ₂=1+2/5=7/5.

(γ₁)/(γ₂)=(5/3)/(7/5)=5/3×5/7.

=(25)/(21).

Why the other options are wrong

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