Practice portal › Kinetic Theory of Gases › Degrees of Freedom and Equipartition
Asked in JEE Main 9th Jan 1st Shift 2020 · Vibrational modes
C_V=f/2R depends on the mode count, not on the molecular mass, so the masses are a distraction.
Gas A is a rigid diatomic: f=3+2=5, so C_V(A)=5/2 R.
Gas B has an additional vibrational mode, which counts twice: f=7, so C_V(B)=7/2 R.
(C_V(A))/(C_V(B))=5/7.
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