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Asked in JEE Main 29th July 2nd Shift 2022 · Escape speed and Brownian motion
A smoke particle in Brownian motion shares the thermal energy of the air, so the same formula applies.
vᵣₘₛ=√(3k_BT)/m with T=273 K at NTP.
3k_BT=3×1.38×10⁻²³×273=1.13×10⁻²⁰.
(3k_BT)/m=(1.13×10⁻²⁰)/(5×10⁻¹⁷)=2.26×10⁻⁴.
vᵣₘₛ=√2.26×10⁻⁴=1.5×10⁻² m/s=15 mm/s.
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