Practice portal › Kinetic Theory of Gases › Speed, Temperature and Molar Mass

Given below are two statements. Statement I: The temperature of a gas is -73°C. When the gas is heated to 527°C, the root mean square speed of the molecules is doubled. Statement II: The product of pressure and volume of an ideal gas will be equal to the translational kinetic energy of the molecules. In the light of the above statements, choose the correct answer from the options given below.

Asked in JEE Main 24th Jan 1st Shift 2023 · Speed with temperature and molar mass

Answer: (4) Statement I is true but Statement II is false.

Step-by-step solution

Statement I: -73°C=200 K and 527°C=800 K.

(v₂)/(v₁)=√(800)/(200)=2, so the rms speed does double. Statement I is true.

Statement II: kinetic theory gives PV=2/3Eₜᵣₐₙₛ, not PV=Eₜᵣₐₙₛ.

The product PV is two thirds of the total translational kinetic energy. Statement II is false.

Why the other options are wrong

More Speed, Temperature and Molar Mass questionsAll Speed, Temperature and Molar Mass questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer