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Asked in JEE Main 12th Jan 2nd Shift 2019 · Pistons and partitions
Let the cylinder's cross-section be A. The upper gas occupies Al₁, the lower Al₂.
Each part holds n moles at the same T, so P₁=(nRT)/(Al₁) (above) and P₂=(nRT)/(Al₂) (below).
The piston is in equilibrium: the gas below must support the gas above plus the piston's weight.
P₂A=P₁A+mg⇒ P₂-P₁=(mg)/A.
(nRT)/A(1/(l₂)-1/(l₁))=(mg)/A, and the A cancels.
m=(nRT)/g((l₁-l₂)/(l₁l₂)).
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