A body of mass M thrown horizontally with velocity v from the top of the tower of height H touches the ground at a distance of 100 m from the foot of the tower. A body of mass 2M thrown at a velocity /v2 from the top of the tower of height 4H will touch the ground at a distance of m.

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100. Horizontal throw: distance = v√(2H)/g = 100 m (mass plays no part). New throw: /v2√(2(4H))/g = /v2·2√(2H)/g = v√(2H)/g = 100 m.

A body of mass M thrown horizontally with velocity v from the top of the tower of height H touches the ground at a distance of 100 m from the foot of the tower. A body of mass 2M thrown at a velocity /v2 from the top of the tower of height 4H will touch the ground at a distance of ______ m.

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