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A water fountain on the ground sprinkles water all around it. If the speed of water coming out of the fountain is v, the total area around the fountain that gets wet is

Asked in AIEEE 2011 · Range and angle of projection

Answer: (2) π(v⁴)/(g²)

Step-by-step solution

Farthest reach Rₘₐₓ = (v²)/g (at 45°), in every direction.

Wet area = π Rₘₐₓ² = (π v⁴)/(g²).

Why the other options are wrong

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