Practice portal › Motion in a Straight Line › Free Fall and Vertical Throws
Asked in JEE Main 29th July 2nd Shift 2022 · Free fall from rest
First half: /h2 = 1/2gt₁² ⇒ t₁ = √/hg.
Whole fall: h = 1/2g(t₁ + t₂)² ⇒ t₁ + t₂ = √(2h)/g = √2 t₁.
t₂ = (√2 - 1)t₁.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer