Practice portal › Motion in a Straight Line › Equations of Uniformly Accelerated Motion
Asked in JEE Main 27th Jan 2nd Shift 2024 · Applying the equations of motion
After 4 cm the speed is (2u)/3: ((2u)/3)² = u² - 2a(0.04) ⇒ 2a(0.04) = (5u²)/9.
From (2u)/3 to rest: 0 = (4u²)/9 - 2ad ⇒ d = (4u²/9)/(2a).
Divide: d/(0.04) = (4/9)/(5/9) = 4/5 ⇒ d = 0.032 m = 32×10⁻³ m.
D = 32.
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