Practice portal › Motion in a Straight Line › Distance, Displacement and Average Speed
Asked in JEE Main 13th April 1st Shift 2023 · Distance and average speed
Speeds: 108 km/h = 30 m/s, 72 km/h = 20 m/s.
To cross the tunnel a train covers the tunnel length plus its own length.
t_A = (L + l)/(30), t_B = (L + 4l)/(20).
With L = 60l: t_A = (61l)/(30), t_B = (64l)/(20) = (16l)/5.
t_B - t_A = (96l - 61l)/(30) = (35l)/(30) = 35 ⇒ l = 30 m.
L = 60l = 1800 m.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer