Practice portal › Motion in a Straight Line › Reading Motion Graphs: Slopes and Areas

The motion of an airplane is represented by the velocity-time graph as shown in the figure. The distance covered by the airplane in the first 30.5 seconds is ______ km.

Asked in JEE Main 23rd Jan 1st Shift 2025 · Area under a graph

Figure: Area under a graph
Answer: (4) 12

Step-by-step solution

Distance is the area under the v–t graph.

0 to 2 s: velocity rises from 200 to 400 m/s, a trapezium of area 1/2(200 + 400)×2 = 600 m.

2 to 30.5 s: constant 400 m/s for 28.5 s, area 400×28.5 = 11400 m.

Total = 600 + 11400 = 12000 m = 12 km.

Why the other options are wrong

More Reading Motion Graphs: Slopes and Areas questionsAll Reading Motion Graphs: Slopes and Areas questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer