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Asked in JEE Main 25th June 2nd Shift 2022 · Orbital velocity
Orbital speed falls off with distance as v=√(GM)/R, so v∝1/(√R).
Therefore (v₁)/(v₂)=√(R₂)/(R₁)=√(800)/(3200).
√1/4=1/2, so the outer satellite is the slower one.
Matching with 1/x gives x=2.
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