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A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only the gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet? [Given: mass of planet =8×10²² kg, radius of planet =2×10⁶ m, gravitational constant G=6.67×10⁻¹¹ N m²/kg²]

Asked in JEE Main 10th April 1st Shift 2019 · Time period of a satellite

• (1) 13
• (2) 9
• (3) 17
• (4) 11

Step-by-step solution

Why the other options are wrong

• (1) Comes from using the surface radius 2×10⁶ m and also trimming the period, which shortens T enough to add revolutions.
• (2) Follows from rounding T up to about 9600 s.
• (3) No clean slip produces 17; using π in place of 2π halves the period and gives about 22 revolutions instead, so this is a filler distractor.

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