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The maximum and minimum distances of a comet from the Sun are 1.6×10¹² m and 8.0×10¹⁰ m respectively. If the speed of the comet at the nearest point is 6×10⁴ m s⁻¹, the speed at the farthest point is

Asked in JEE Main 16th March 1st Shift 2021 · Second law and areal velocity

Answer: (1) 3.0×10³ m s⁻¹

Step-by-step solution

Angular momentum about the Sun is conserved, and at the nearest and farthest points the velocity is perpendicular to the radius.

The comet is slowest at the farthest point, so vₘᵢₙrₘₐₓ=vₘₐₓrₘᵢₙ.

(rₘᵢₙ)/(rₘₐₓ)=(8.0×10¹⁰)/(1.6×10¹²)=1/(20).

vₘᵢₙ=(6×10⁴)/(20)=3.0×10³ m s⁻¹.

Why the other options are wrong

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