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If a satellite orbiting the earth is 9 times closer to the earth than the moon, what is the time period of rotation of the satellite? Given: the rotational time period of the moon is 27 days, and the gravitational attraction between the satellite and the moon is neglected.

Asked in JEE Main 23rd January 2nd Shift 2025 · Third law

Answer: (1) 1 day

Step-by-step solution

Both bodies orbit the same earth, so Kepler's third law applies directly: T∝ r^3/2.

Being 9 times closer means rₛ=(rₘ)/9.

Tₛ=27×(1/9)^3/2=(27)/(27)=1 day.

Why the other options are wrong

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