Practice portal › Experimental Skills › Surface Tension, Viscosity and Calorimetry
Asked in JEE Main 2017 · Surface tension, viscosity and calorimetry
Idea: the last digit quoted sets the uncertainty, so Δ D=Δ h=0.01×10⁻² m.
T∝ rh∝ Dh, so (Δ T)/T=(Δ D)/D+(Δ h)/h.
=(0.01)/(1.25)+(0.01)/(1.45)=0.0080+0.0069=0.0149.
That is 1.49%, closest to 1.5%.
g carries no error here, and the numerical factor 1/2×10³ is exact, so neither contributes.
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