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The electric field of a plane electromagnetic wave is given by E⃗ = E₀ ı̂ cos(kz) cos(ω t). The corresponding magnetic field B⃗ is then given by

Asked in JEE Main 10th April 1st Shift 2019 · Direction of travel and standing waves

Answer: (1) B⃗ = (E₀)/c ȷ̂ sin(kz) sin(ω t)

Step-by-step solution

cos(kz)cos(ω t) is a standing wave, so B is not simply E/c times the same factor — use abla × E⃗ = -∂B⃗/∂ t

with Eₓ = E₀ cos(kz)cos(ω t), abla × E⃗ = (∂ Eₓ/∂ z) ȷ̂ = - E₀k sin(kz)cos(ω t) ȷ̂

so ∂B⃗/∂ t = E₀k sin(kz)cos(ω t) ȷ̂ ⇒ B⃗ = (E₀k/ω) sin(kz)sin(ω t) ȷ̂ = (E₀/c) sin(kz)sin(ω t) ȷ̂

Why the other options are wrong

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