Practice portal › Electromagnetic Waves › The Plane Wave: Reading the Equation
Asked in JEE Main 10th April 1st Shift 2019 · Direction of travel and standing waves
cos(kz)cos(ω t) is a standing wave, so B is not simply E/c times the same factor — use abla × E⃗ = -∂B⃗/∂ t
with Eₓ = E₀ cos(kz)cos(ω t), abla × E⃗ = (∂ Eₓ/∂ z) ȷ̂ = - E₀k sin(kz)cos(ω t) ȷ̂
so ∂B⃗/∂ t = E₀k sin(kz)cos(ω t) ȷ̂ ⇒ B⃗ = (E₀k/ω) sin(kz)sin(ω t) ȷ̂ = (E₀/c) sin(kz)sin(ω t) ȷ̂
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