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An electromagnetic wave of frequency u = 3.0 MHz passes from vacuum into a dielectric medium with permitivity ε = 4.0. Then

Asked in JEE Main 2004 · Crossing an interface

Answer: (3) wavelength is halved and frequency remains unchanged

Step-by-step solution

n = √εᵣ = √4 = 2 (non-magnetic dielectric), so v = c/2

the frequency is set by the source and does not change at the interface: u stays 3.0 MHz

λ = v/ u, so λₘedium = λᵥacuum/2 — halved

Why the other options are wrong

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