Practice portal › Electric Potential and Capacitance › Capacitor Circuits and Energy
Asked in JEE Main 2007 · Battery connected or removed
The slab is moved out and then brought back, so the capacitor ends in exactly the state it started in: the same charge, the same capacitance C and the same potential V.
Energy is a function of state, so Δ U=U_final-Uᵢₙᵢₜᵢₐₗ=0.
The process is carried out slowly, so there is no kinetic energy left over and no dissipation.
Hence the net work done by the system over the complete cycle is zero: whatever work is done against the attractive pull while pulling the slab out is recovered when it is drawn back in.
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