The given graph shows the variation (with distance r from the centre) of [the plotted quantity stays constant from r=0 up to r=r₀ and then falls off, tending to zero as r increases; r₀ is the radius of the charged body shown beside the graph]

Question

Accepted Answer

(3) Potential of a uniformly charged spherical shell. The plotted quantity is constant for r<r₀ and then decays towards zero for r>r₀. For a thin shell, all the charge sits on r=r₀, so no work is needed to move a test charge inside it: V=(kQ)/(r₀) everywhere in the cavity, a horizontal line. Outside, the shell behaves as a point charge, so V=(kQ)/r falls off and tends to zero. Only the potential of a uniformly charged spherical shell has both features, so option (c) is the graph.

The given graph shows the variation (with distance r from the centre) of [the plotted quantity stays constant from r=0 up to r=r₀ and then falls off, tending to zero as r increases; r₀ is the radius of the charged body shown beside the graph]

Step-by-step solution

Why the other options are wrong