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Asked in JEE Main 2005 · Infinite sheet and sheet combinations
The sheet is vertical, so its field E=σ/(2ε₀) is horizontal and pushes the ball away, and θ is measured from the vertical sheet.
Three forces act on the ball: weight mg down, electric force qE horizontal, and tension T along the thread.
Resolving along and across the vertical: T cos θ=mg and T sin θ=qE.
Dividing, tan θ=(qE)/(mg)=(qσ)/(2ε₀mg).
Everything except σ and θ is fixed, so σ∝tan θ.
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