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Asked in JEE Main 28th June 2nd Shift 2022 · Field of discrete charges
The charges are unlike, so at the midpoint both fields point from A towards B and their magnitudes add.
Each charge is d/2 from O, so E=2·(kq)/((d/2)²)=(8kq)/(d²).
8kq=8×9×10⁹×8×10⁻⁶=5.76×10⁵.
d²=(5.76×10⁵)/(6.4×10⁴)=9 m².
d=3.0 m.
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