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Asked in JEE Main 4th April 1st Shift 2025 · Torque, energy and work done
The two equal and opposite charges on a rigid rod form a dipole: p=qL=2×10⁻⁶×0.20=4×10⁻⁷ C m.
An infinite non-conducting sheet gives E=σ/(2ε₀)=(100×10⁻⁶)/(2×8.85×10⁻¹²)=5.65×10⁶ N C⁻¹.
Torque on a dipole: τ=pE sin θ with θ=30°.
τ=4×10⁻⁷×5.65×10⁶×0.5=1.13 N m.
So τ=1.13 N m; the paper prints 1.12 N m (option 3), which is 1.1299 truncated rather than rounded. (The masses play no part; they would matter only for the angular acceleration.)
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