The force between two point charges q₁ and q₂ placed in vacuum r cm apart is F. The force between them when they are placed in a medium of dielectric constant k=5 at a separation of r/5 cm will be

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(3) 5F. In vacuum F=1/(4πε₀)(q₁q₂)/(r²). In a medium of dielectric constant k the force is reduced by k: F'=1/(4πε₀ k)(q₁q₂)/(r'²). With r'=r/5, the factor 1/(r'²)=(25)/(r²). F'=(25)/5F=5F.

The force between two point charges q₁ and q₂ placed in vacuum r cm apart is F. The force between them when they are placed in a medium of dielectric constant k=5 at a separation of r/5 cm will be

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