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If the de Broglie wavelength of an electron is equal to 10⁻³ times the wavelength of a photon of frequency 6×10¹⁴ Hz, then the speed of electron is equal to (Speed of light =3×10⁸ m/s, Planck's constant =6.63×10⁻³⁴ J s, Mass of electron =9.1×10⁻³¹ kg)

Asked in JEE Main 11th Jan 1st Shift 2019 · Matter wave against photon

Answer: (3) 1.45×10⁶ m/s

Step-by-step solution

Photon: λₚₕ=c/u=(3×10⁸)/(6×10¹⁴)=5×10⁻⁷ m.

Electron: λₑ=10⁻³λₚₕ=5×10⁻¹⁰ m.

v=h/(mλₑ)=(6.63×10⁻³⁴)/(9.1×10⁻³¹×5×10⁻¹⁰).

v=1.45×10⁶ m s⁻¹.

Why the other options are wrong

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