Practice portal › Dual Nature of Matter and Radiation › Photon Energy, Number of Photons and Intensity
Asked in JEE Main Online 2014 · Counting photons
Threshold: λ₀=(12400)/(2.3)=5391 A, so only the 4972 A half ejects electrons.
That half carries 1.8×10⁻³ Wm⁻²; on 10⁻⁴ m² for 2 s it delivers 3.6×10⁻⁷ J.
Photon energy: (12400)/(4972)=2.49 eV =3.99×10⁻¹⁹ J.
N=(3.6×10⁻⁷)/(3.99×10⁻¹⁹)≈9×10¹¹.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer