Practice portal › Dual Nature of Matter and Radiation › Charged Particles in Electric and Magnetic Fields
Asked in JEE Main 9th Jan 1st Shift 2020 · Magnetic field and circular paths
Given: λ=6561 A, B=3×10⁻⁴ T, r=10⁻² m.
v=(eBr)/m=(1.6×10⁻¹⁹×3×10⁻⁴×10⁻²)/(9.1×10⁻³¹)=5.3×10⁵ m s⁻¹.
K=1/2 mv²=1.26×10⁻¹⁹ J =0.79 eV.
E=(12400)/(6561)=1.89 eV, so φ=1.89-0.79≈1.1 eV.
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