Practice portal › Current Electricity › Electrical Energy and Power

Different combination of 3 resistors of equal resistance R are shown in the figures. The increasing order for power dissipation is [Figure: the same current I enters each combination. (A) two R in parallel, then one R in series. (B) two R in series, that pair in parallel with one R. (C) three R in parallel. (D) three R in series.]

Asked in JEE Main 13th April 1st Shift 2023 · Heating and power in resistors

Figure: Heating and power in resistors
Answer: (4) P_C<P_B<P_A<P_D

Step-by-step solution

Same current I in each, so P=I²R_eq and order follows R_eq.

(A) R/2+R=1.5R. (B) (2R· R)/(3R)=(2R)/3.

(C) R/3. (D) 3R.

Increasing: P_C<P_B<P_A<P_D.

Why the other options are wrong

More Electrical Energy and Power questionsAll Electrical Energy and Power questions →

Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.

Practise this with a timer