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Asked in JEE Main 11th Jan 2nd Shift 2019 · Metre bridge
Initially (R₁)/(R₂)=(40)/(60)=2/3.
Adding 10 Ω to the left raises the null point to 50 cm: R₁+10=R₂.
Solving: R₂=30 Ω, R₁=20 Ω.
To return to 40 cm the left gap must be 20 Ω: (30x)/(30+x)=20.
x=60 Ω.
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