[Figure: a ladder with three 1 Ω rungs. Top rail from left: a 2 V cell, first rung node, a 2 V cell, second rung node, a 2 V cell, then to the third rung at the right end. Bottom rail from left: a 2 V cell, first rung node, a 2 V cell, second rung node, a 2 V cell, then to the third rung. The left…

Question

[Figure: a ladder with three 1 Ω rungs. Top rail from left: a 2 V cell, first rung node, a 2 V cell, second rung node, a 2 V cell, then to the third rung at the right end. Bottom rail from left: a 2 V cell, first rung node, a 2 V cell, second rung node, a 2 V cell, then to the third rung. The left ends of the two rails are joined by a wire. All six cells have the same orientation, positive terminal toward the left.] In the above circuit the current in each resistance is

Accepted Answer

(4) 0 A. Take the joined left end as 0 V. Each cell has its positive terminal on the left, so moving right across a cell the potential falls by 2 V. Top and bottom rails fall together: both ends of the first rung are at -2 V, of the second at -4 V and of the third at -6 V. Every 1 Ω resistor has zero potential difference, so the current in each is 0 A.

Step-by-step solution

Why the other options are wrong