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Asked in JEE Main 18th March 2nd Shift 2021 · Resistance of a wire and stretching
Each wire: Rᵢ=(ρᵢ l)/A. In parallel, R=(ρ₁ρ₂)/(ρ₁+ρ₂)l/A=(18)/9l/A=2l/A.
The combination is a conductor of length l and area 2A.
ρ_eff=(R×2A)/l=4 Ω cm.
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