A hollow cylindrical conductor has length of 3.14 m, while its inner and outer diameters are 4 mm and 8 mm respectively. The resistance of the conductor is n×10⁻³ Ω. If the resistivity of the material is 2.4×10⁻⁸ Ω m. The value of n is .

Question

Accepted Answer

2. Radii: r₁=2 mm, r₂=4 mm; area A=π(r₂²-r₁²)=π(16-4)×10⁻⁶=12π×10⁻⁶ m². R=(ρ l)/A=(2.4×10⁻⁸×3.14)/(12×3.14×10⁻⁶). R=2×10⁻³ Ω, so n=2.

A hollow cylindrical conductor has length of 3.14 m, while its inner and outer diameters are 4 mm and 8 mm respectively. The resistance of the conductor is n×10⁻³ Ω. If the resistivity of the material is 2.4×10⁻⁸ Ω m. The value of n is ______.

Step-by-step solution