The number density of free electrons in copper is nearly 8×10²⁸ m⁻³. A copper wire has its area of cross section =2×10⁻⁶ m² and is carrying a current of 3.2 A. The drift speed of the electrons is ×10⁻⁶ m s⁻¹.

Question

Accepted Answer

125. v_d=I/(neA). neA=8×10²⁸×1.6×10⁻¹⁹×2×10⁻⁶=2.56×10⁴. v_d=(3.2)/(2.56×10⁴)=1.25×10⁻⁴=125×10⁻⁶ m/s.

The number density of free electrons in copper is nearly 8×10²⁸ m⁻³. A copper wire has its area of cross section =2×10⁻⁶ m² and is carrying a current of 3.2 A. The drift speed of the electrons is ______ ×10⁻⁶ m s⁻¹.

Step-by-step solution