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The resistance of the series combination of two resistances is S. When they are joined in parallel the total resistance is P. If S=nP, then the minimum possible value of n is

Asked in JEE Main 2004 · Series and parallel combinations

Answer: (1) 4

Step-by-step solution

S=R₁+R₂ and P=(R₁R₂)/(R₁+R₂).

n=S/P=((R₁+R₂)²)/(R₁R₂).

By AM-GM, (R₁+R₂)²≥4R₁R₂, with equality when R₁=R₂.

Minimum n=4.

Why the other options are wrong

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