Practice portal › Current Electricity › Combination of Resistors
Asked in JEE Main 2004 · Series and parallel combinations
S=R₁+R₂ and P=(R₁R₂)/(R₁+R₂).
n=S/P=((R₁+R₂)²)/(R₁R₂).
By AM-GM, (R₁+R₂)²≥4R₁R₂, with equality when R₁=R₂.
Minimum n=4.
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