Practice portal › Current Electricity › Electrical Energy and Power
Asked in JEE Main Online 2012 · Rated bulbs and appliances
The bulbs are in parallel, so both have V=6 V.
P=(V²)/R: bulb 1 gets (36)/3=12 W and bulb 2 gets (36)/6=6 W.
Bulb 1 dissipates more power and glows more.
Reading this solution needs no sign-in. You only sign in to practise against the clock and keep your progress.
Practise this with a timer