A uniform metallic wire carries a current 2 A, when 3.4 V battery is connected across it. The mass of uniform metallic wire is 8.92×10⁻³ kg, density is 8.92×10³ kg/m³ and resistivity is 1.7×10⁻⁸ Ω m. The length of wire is

Question

Accepted Answer

(1) l=10 m. R=V/I=(3.4)/2=1.7 Ω Volume =m/d=(8.92×10⁻³)/(8.92×10³)=10⁻⁶ m³, and A=(Vol)/l. R=(ρ l)/A=(ρ l²)/(Vol)⇒ l²=(R Vol)/ρ=(1.7×10⁻⁶)/(1.7×10⁻⁸)=100 l=10 m

A uniform metallic wire carries a current 2 A, when 3.4 V battery is connected across it. The mass of uniform metallic wire is 8.92×10⁻³ kg, density is 8.92×10³ kg/m³ and resistivity is 1.7×10⁻⁸ Ω m. The length of wire is

Step-by-step solution

Why the other options are wrong