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Equivalent resistance between the adjacent corners of a regular n-side polygon of uniform wire of resistance R would be

Asked in JEE Main 1st Feb 2nd Shift 2023 · Wires bent into shapes

Answer: (4) ((n-1)R)/(n²)

Step-by-step solution

Each side has resistance R/n.

Between adjacent corners: one side R/n in parallel with the other n-1 sides, ((n-1)R)/n.

R_eq=(R/n·((n-1)R)/n)/(R/n+((n-1)R)/n)=((n-1)R²/n²)/R

R_eq=((n-1)R)/(n²)

Why the other options are wrong

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