A galvanometer (G) of 2 Ω resistance is connected in the given circuit. The ratio of charge stored in C₁ and C₂ is [Figure: a diamond with left vertex L, top T, right M, bottom D. L to T: 4 Ω; T to M: capacitor C₂=6 μF; L to D: capacitor C₁=4 μF; D to M: 6 Ω. Galvanometer G joins T to D. A 6 V cell…

Question

A galvanometer (G) of 2 Ω resistance is connected in the given circuit. The ratio of charge stored in C₁ and C₂ is [Figure: a diamond with left vertex L, top T, right M, bottom D. L to T: 4 Ω; T to M: capacitor C₂=6 μF; L to D: capacitor C₁=4 μF; D to M: 6 Ω. Galvanometer G joins T to D. A 6 V cell is connected between L and M by an outer loop.]

Accepted Answer

(4) 1/2. In steady state the capacitors carry no current, so current flows L→4 Ω→ T→ G→ D→6 Ω→ M. I=6/(4+2+6)=0.5 A; drops: 2 V, 1 V, 3 V. C₁ is across L and D: V₁=2+1=3 V, Q₁=4×3=12 μC. C₂ is across T and M: V₂=1+3=4 V, Q₂=6×4=24 μC. Q₁:Q₂=1:2

Step-by-step solution

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