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In a hydrogen spectrum, λ be the wavelength of first transition line of Lyman series. The wavelength difference will be aλ between the wavelength of 3^rd transition line of Paschen series and that of 2^nd transition line of Balmer Series where a= ______.

Asked in JEE Main 26th July 1st Shift 2022 · Spectral series and wavelengths

Answer: 5

Step-by-step solution

λ=4/(3R).

Third Paschen line 6→3: R(1/9-1/(36))=R/(12), λ_P=(12)/R.

Second Balmer line 4→2: λ_B=(16)/(3R).

λ_P-λ_B=(20)/(3R)=5λ

→ 5

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