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The shortest wavelength of the spectral lines in the Lyman series of hydrogen spectrum is 915 A. The longest wavelength of spectral lines in the Balmer series will be ______ A.

Asked in JEE Main 5th April 2nd Shift 2024 · Spectral series and wavelengths

Answer: 6588

Step-by-step solution

1/R=915 A

Longest Balmer 3→2: λ=(36)/(5R)=7.2×915=6588 A

→ 6588

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