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A photon is emitted in transition from n=4 to n=1 level in hydrogen atom. The corresponding wavelength for this transition is (given, h=4×10⁻¹⁵ eVs)

Asked in JEE Main 24th Jan 2nd Shift 2023 · Spectral series and wavelengths

Answer: (4) 94.1 nm

Step-by-step solution

Δ E=13.6(1-1/(16))=12.75 eV

λ=(hc)/(Δ E)=(4×10⁻¹⁵×3×10⁸)/(12.75)=9.41×10⁻⁸ m

λ=94.1 nm

Why the other options are wrong

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