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Asked in JEE Main 24th Jan 2nd Shift 2023 · Spectral series and wavelengths
Δ E=13.6(1-1/(16))=12.75 eV
λ=(hc)/(Δ E)=(4×10⁻¹⁵×3×10⁸)/(12.75)=9.41×10⁻⁸ m
λ=94.1 nm
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