The energy of an electron in an orbit of the Bohr's atom is -0.04E₀ eV, where E₀ is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then (2π L)/h is .

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Accepted Answer

(2) 5. Eₙ=(E₀)/(n²), so 1/(n²)=0.04=1/(25) and n=5. L=(nh)/(2π), so (2π L)/h=n=5.

The energy of an electron in an orbit of the Bohr's atom is -0.04E₀ eV, where E₀ is the ground state energy. If L is the angular momentum of the electron in this orbit and h is the Planck's constant, then (2π L)/h is ______.

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