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A series LCR circuit has R=80 Ω, X_L=100 Ω and X_C=40 Ω. The input voltage is 2500 cos(100π t) V. The current amplitude is ______ A.

Asked in JEE Main 31st Jan 2nd Shift 2023 · Current in a series LCR

Answer: 25

Step-by-step solution

Z=√80²+(100-40)²=√6400+3600=100 Ω.

Peak voltage V₀=2500 V, so I₀=(2500)/(100)=25 A.

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