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A series LCR circuit with L=(100)/π mH, C=(10⁻³)/π F and R=10 Ω is across a 220 V, 50 Hz supply. The power factor is ______.

Asked in JEE Main 27th Jan 2nd Shift 2024 · Power factor

Answer: 1

Step-by-step solution

X_L=2π f L=2π(50)(100)/π×10⁻³=10 Ω.

X_C=1/(2π f C)=1/(2π(50)(10⁻³)/π)=10 Ω.

X_L=X_C: resonance, Z=R, so power factor =1.

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