Practice portal › Alternating Current › AC Through R, L and C
Asked in JEE Main 28th Jan 2nd Shift 2026 · Behaviour of R, L and C separately
Power: Iᵣₘₛ² R=32⇒ R=(32)/(2²)=8 Ω.
Energy: 1/2 L Iᵣₘₛ²=16⇒ L=(2×16)/(2²)=8 H.
X_L=2π f L=2π(50)(8)=800π Ω; (X_L)/R=(800π)/8=100π=314.
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