The distance between the two slits in Young's experiment is 0.1 mm and the distance of the screen from the slits is 100 cm. If the wavelength of the light is 5000 A, the width of a fringe is

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(1) 5 mm. Given: d=0.1 mm=10⁻⁴ m, D=100 cm=1 m, λ=5000 A=5×10⁻⁷ m. Idea: the fringe width is the spacing between consecutive bright fringes, β=(λ D)/d. β=(5×10⁻⁷×1)/(10⁻⁴). β=5×10⁻³ m. β=5 mm.

The distance between the two slits in Young's experiment is 0.1 mm and the distance of the screen from the slits is 100 cm. If the wavelength of the light is 5000 A, the width of a fringe is

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